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0=30x^2-35x+10
We move all terms to the left:
0-(30x^2-35x+10)=0
We add all the numbers together, and all the variables
-(30x^2-35x+10)=0
We get rid of parentheses
-30x^2+35x-10=0
a = -30; b = 35; c = -10;
Δ = b2-4ac
Δ = 352-4·(-30)·(-10)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-5}{2*-30}=\frac{-40}{-60} =2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+5}{2*-30}=\frac{-30}{-60} =1/2 $
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